Question

Here is one kind of similar to the last one if anyone was good at the converging/diverging problems :)

Answer 1

Question #1

Answer 2

this counts as algebra?

Answer 3

here is the deal, if you are not familiar with these
as \(n\to \infty\) anything like \(\frac{1}{n}\) or \(\frac{5}{n}\) or \(\frac{(-1)^n}{n}\) goes to zero

Answer 4

since that stuff goes to zero, and you have
\[\frac{(-1)^n}{n}+3\] as \(n\to \infty\) the terms get close and closer to \(3\)

Answer 5

Apparently it does, and now I see thank you! You have been a great help!

Answer 6

yw, glad to help
this is usually done in some more advanced classes because it takes a minute to get a real definition of
\[\lim_{n\to \infty}a_n=L\]