Question

True or false
Will medal


((2x-1)/(x+1))/((3x^2)/(x^2+x))=(2x-1)/(3x)
And is it in reduced form

Answer 1

@DanJS

Answer 2

\[\frac{ \frac{ 2x-1 }{ x+1 } }{ \frac{ 3x^2 }{ x^2+x } }\]

that

Answer 3

notice in the very bottom denominator, you have x^2+x which can factor to be x(x+1)

Answer 4

flip the bottom fraction over, and multiply it to the top fraction instead of divide

Answer 5

\[\frac{ 2x-1 }{ x+1 }*\frac{ x(x+1) }{ 3x^2 } = \frac{ 2x-1 }{ 3x }\]

Answer 6

Yay so it's true

Answer 7

idk, have to continue with the left side, multiply it by

Answer 8

cancel out (x+1) from the top and bottom on the left

Answer 9

When you multiply fractions it is just
\[\frac{ a }{ b }*\frac{ c }{ d } = \frac{ ac }{ bd }\]

Answer 10

so the left side becomes
\[\frac{ x*(2x-1)(x+1) }{ 3x^2(x+1) } = \frac{ 2x-1 }{ 3x }\]

Answer 11

cancel common factors in the top and bottom , and see what you get

Answer 12

Maybe this will make it more clear

\[\frac{ x*(x+1)*(2x-1) }{ 3*x*x*(x+1) }\]

cancel what is common in top and bottom, then does it equal the right side of the original equation, true or false

Answer 13

Yes I get 2x-1/3x

Answer 14

so then true

Answer 15

Thank you

Answer 16

welcome