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OpenStudy (anonymous):
OpenStudy (sleepyjess):
Welcome to OpenStudy! First off, one question, why does it say Lesson 4: Semester Test at the top?
OpenStudy (anonymous):
its a study guide for the test
OpenStudy (sleepyjess):
Mmmm ok, let me figure out how to do this first?
OpenStudy (anonymous):
ok
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OpenStudy (sleepyjess):
|dw:1420782366305:dw|
OpenStudy (sleepyjess):
Does that make sense?
OpenStudy (anonymous):
yes! but how am I supposed to prove it
OpenStudy (anonymous):
that came out sounding rude srry about that
OpenStudy (sleepyjess):
Ok, now, we know that for every 1.5 meters tall, there is 8 meters of shadow. We can use this information to find the height of the flagpole and building. The shadow is \(\sf 5.\overline{333}*h\).
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OpenStudy (sleepyjess):
Now, we can transfer that to \(\sf\dfrac{s}{5.\overline{333}}=h\).
OpenStudy (anonymous):
so now we
OpenStudy (sleepyjess):
Now, we take the shadow length of the flagpole and substitute it for s.
OpenStudy (sleepyjess):
Lets see if @Kainui can confirm my thoughts on this problem?
OpenStudy (anonymous):
alright
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OpenStudy (sleepyjess):
or possibly @nincompoop
OpenStudy (sleepyjess):
@Jhannybean
OpenStudy (anonymous):
well thanks for taking time to help !!! appreciate it
OpenStudy (sleepyjess):
No problem! Do you get how to do it now?
OpenStudy (jhannybean):
Try similar triangles.
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OpenStudy (jhannybean):
Are you stuck on part a) or part b)?
OpenStudy (sleepyjess):
Does the method I used also work?
OpenStudy (jhannybean):
|dw:1420783950369:dw|
OpenStudy (jhannybean):
I'm not really sure where the 5.33 came from @sleepyjess
OpenStudy (sleepyjess):
I did 8/1.5
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OpenStudy (jhannybean):
okay, then that would be \[\frac{8}{1.5} = \frac{8+32}{x}\] right? that's what you did?