Determine if the complex number, 2+ i, is a solution to the quadratic equation 3x2 - 6x + 6 = 0 Explain your answer.
hi easiest just to solve if and see what you get
\[3x^2-6x+6=0\] divide by 3 and solve \[x^2-2x+2=0\] you know how to solve this one?
Plug in 2 + i to your equation
probably easiest in this case to complete the square because 2 is even it will be real annoying to try to evaluate it at \(x=2+i\)
the answer will probably be no in any case
Can you please explain why it is not a solution
sure when we solve it we will get something else!
Okay thank you . Could you help me with one more?
\[x^2-2x+2=0\\ x^2-2x=-2\\ (x-1)^2=-2+1=-1\\ x-1=\pm i\\ x=1\pm i\]
the solutions are \(1\pm i\) not \(2\pm i\)
sure why not?
Determine if 1 - i is a solution to the equation 2x2 - 4x + 4 = 0. Explain your answer.
lol this is really sooo much different than the last one why don't they just ask you to solve it instead of screwing around with "is blah blah..."
\[2x^2-4x+4=0\] divide by 2 \[x^2-2x+2=0\] subtract 2 \[x^2-2x=-2\] complete the square \[(x-1)^2=-2+1=-1\] take the square root \[x-1=\pm i\] solve for \(x\)\[x=1\pm i\]
so this time the answer is YES
Thank you so much!
you are welcome dear glad to help!
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