Question

Need help with Algebra 2!!!

Answer 1

Help me simplify this
\[\frac{ 3-\frac{ 3 }{ x+1 } }{ \frac{ 3 }{ x+1 } }\]

Answer 2

first change \(3\) so that it has a common denominator with \(-\dfrac{3}{x+1}\)

Answer 3

that means multiplying both top and bottom of \(\dfrac{3}{1}\) by \(x+1\)

Answer 4

Then wouldn't the 3 be 3x+3?

Answer 5

Over what?

Answer 6

\[\frac{3}{1} \cdot \frac{x+1}{x+1}\]

Answer 7

\[\frac{ 3-\frac{ 3 }{ x+1 } }{ \frac{ 3 }{ x+1 } }\times \frac{x+1}{x+1}\]

Answer 8

That works too.

Answer 9

yeah i like that way best
cancel cancel cancel\[\cancel{}\]

Answer 10

How did you know that you were supposed to multiply by x+1?

Answer 11

Because one number is subtracting a fraction, in order to combine them, you must turn the number into a fraction

Answer 12

Or simply cancel out the fraction, as @misty1212 showed us, \(\left(3 -\dfrac{3}{x+1}\right)\cdot x+1\)

Answer 13

Using this method, treat \((x+1)\) as like a number, and use the distributive property cancel out the fraction, and multiply the number.

Answer 14

Alright, thanks!!!

Answer 15

No problem :D