Question

How many complex roots does 5x6+x4-3=0
3
4
5
6

Answer 1

For finding the roots, use the discriminant: \(b^2-4ac\)

Answer 2

Your function is in quadratic form: \(ax^2+bx+c=0\)

Answer 3

Orr rather, I think you can look a it this way, \[5x^6+x^4-3=0\] Highest power of \(x\) is \(6\), therefore you will have 6 roots. Complex roots always come in conjugate pairs, meaning \(a\pm bi\)

The following can be solutions:

- 6 real, no complex

- 4 real, 2 complex (1 conjugate pair)

- 2 real , 4 complex (2 conjugate pairs)

- 0 real, 6 complex, (3 conjugate pairs)