Question

**really quickly need help!!! simplify complex expression!

Answer 1

I know the process somewhat on how to solve it!

Answer 2

@iambatman could you help with this?

Answer 3

@sammixboo ? i am just tagging people who have high statuses next to their name lol sorry!

Answer 4

have you tried multiplying top and bottom by "x" ?

Answer 5

no! is that the LCD?

Answer 6

i know you find the LCD and then from there you multiply each but i cant figure out the LCD.

Answer 7

if it helps think of 1 as 1/1 and 4 as 4/1

Answer 8

\[\large \dfrac{~~1+\frac{2}{x}~~}{4-\frac{6}{x}}\]

is same as

\[\large \dfrac{~~\frac{1}{1}+\frac{2}{x}~~}{\frac{4}{1}-\frac{6}{x}}\]

Answer 9

okay, but how would i start to solve when i cant solve them without the same denominator?

Answer 10

thats right! you need same thing on denominator to add fractions

Answer 11

\[\large \dfrac{~~1+\frac{2}{x}~~}{4-\frac{6}{x}} \cdot \frac{x}{x}\]

Answer 12

okay! haha thats the part im having diffculties with.

Answer 13

You can eliminate the x's much faster

Answer 14

okay so by multiplying by x are you canceling out the x completely?

Answer 15

Distribute it to all the terms in the numerator and denominator

Answer 16

okay so

Answer 17

for the top? is that correct?

Answer 18

\[\large \dfrac{~~1+\frac{2}{x}~~}{4-\frac{6}{x}} \cdot \frac{x}{x} = \frac{(1+\frac{2}{x})\cdot x}{(4-\frac{6}{x})\cdot x } \]

Answer 19

No it is not,

Answer 20

agh then im confused.

Answer 21

what do you do with multiplying by x?

Answer 22

what is \((1)(x)\) and \(\dfrac{2}{x} \cdot x\)?

Answer 23

im just seeing what i got above! haha