Solve the equation Log(x+7) - logx = 3
ok in this case you can combine the two logs
What makes this case different?
2 logs with same base
Log x?
Remember, \(\log(a) + \log(b) = \log(ab)\) and \(\log(a)-\log(b) = \dfrac{\log(a)}{\log(b)}\)
What I really hate about algebra is, I get an x and I wonder y.
So combine them, @BabyKay
What @Jhannybean meant was\[\log_{c}a -\log_{c}b =\log_{c}\frac{ a }{ b }\]
the choices are 3.5, 142.7, 0.0070, and 0.0707.
I don't care what the choices are, You need to learn how to solve.
I just wanna catch up on my work b4 the semester ends
I got the answer anyway....it's 0.0070
Here's an example:\[\log_{3}(x -2)-\log_{3}(x +1)=2 \]\[\log_{3}\frac{ x -2 }{ x +1 } =2\]Now convert logarithm form to exponential form, to get\[\frac{ x -2 }{ x +1 }=3^{2}\]Now multiply both sides by (x + 1), to get\[x -2=9(x +1)\]\[x -2=9x +9\]Solving for x, we get\[x =-\frac{ 11 }{ 8 }\]Keep in mind the restriction in the problem: x > 2. Hence we have no solution for this example but the answer to your question is correct.
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