Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
@mathmath333
@iGreen
@iambatman
OpenStudy (anonymous):
@purplepiggy171
@Radelp
OpenStudy (anonymous):
anyone? know? how? to? do? these?
OpenStudy (anonymous):
sorry, im lost o_o
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@SolomonZelman
OpenStudy (igreen):
First we find the slope..
\(m = \dfrac{y_2-y_1}{x_2-x_1}\)
Let's take the two points they give us: \((1.5, 2)\) and \((-4, -1)\) and plug them in:
\(m = \dfrac{2 + 1}{1.5 + 4}\)
Can you solve that? @bellaboo258
OpenStudy (anonymous):
@One098
OpenStudy (igreen):
@Radelp I got it covered :)
OpenStudy (anonymous):
okay
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hold on im finding the slope
OpenStudy (igreen):
After we find the slope, we can locate the y-intercept, and plug it into slope-intercept form, which is \(\sf y = mx + b\), then we can re-arrange it into standard form \(\sf Ax + By = C\).
OpenStudy (igreen):
Okay, @bellaboo258 tell me what you get.
OpenStudy (anonymous):
|dw:1420812408891:dw|
OpenStudy (anonymous):
@iGreen
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (igreen):
Yes, I got the same thing.
OpenStudy (anonymous):
nowww wuut?
OpenStudy (igreen):
Now we find the y-intercept..which is where the line crosses the y-axis..and where's that?
OpenStudy (anonymous):
im like really bad at this..
OpenStudy (anonymous):
at 1? on the y axis?
Still Need Help?
Join the QuestionCove community and study together with friends!