Question

help long equation will post bellow

Answer 1

okay

Answer 2

When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ?

F. 4
G. 14
H. 16
J. 20
K. 50

Answer 3

First find their values..

\(3x^2 - 2y\)

Plug in x = 3 and y = 5:

\(3(3)^2 - 2(5)\)

Can you simplify \(3^2\)?

Answer 4

9

Answer 5

Yes..so that gives us:

\(3(9) - 2(5)\)

Now multiply both of those and subtract.

Answer 6

27-10

Answer 7

Yep, subtract that.

Answer 8

17

Answer 9

Okay, so that one equals 17, now let's find the other one.

\(2x^2 – 3y\)

Plug in x = 3 and y = 5:

\(2(3)^2 - 3(5)\)

What's \(3^2\)?

Answer 10

3x^2-2y = 3(3^2)-3(5) = 27-15 = 12
---
2x^2 - 3y = 2(3)^2-3(5) = 18-15 = 3
-------
Ans: 12-3 =

Answer 11

What's \(3^2\)? @Indogot

Answer 12

sorry @iGreen internet died

Answer 13

but 9

Answer 14

yes it's 9 good job :)

Answer 15

18-15=3

Answer 16

got it subtract 3 from 17 get 14

Answer 17

G
gg