BM = 2x + 3, DM = 3x - 2, AM = 3y - 2, and CM = 2y+4. If ABCD is a parallelogram, what is the value of x?
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OpenStudy (anonymous):
OpenStudy (anonymous):
a) x=1, y = 2
b) x =5, y =6
c) x =1, y= 6
d) x = 5, y = 2
OpenStudy (anonymous):
I think it's b.
Directrix (directrix):
I think we need to do a little bit of Algebra.
The diagonals of a parallelogram bisect each other.
So, BM = DM
Solve for x:
2x + 3 = 3x - 2 ---> @OmiLala
OpenStudy (anonymous):
So d?
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Directrix (directrix):
Please solve this for x:
2x + 3 = 3x - 2 ---> @OmiLala
Subtract 2x from each side of the equation. What do you get?
OpenStudy (anonymous):
1
OpenStudy (anonymous):
x = 1...
OpenStudy (anonymous):
and y = 2
Directrix (directrix):
2x + 3 = 3x - 2
-2x -2x
===============
3 = x - 2
Add 2 to both sides of that equation to solve for x.
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Directrix (directrix):
x = 1... NOT correct
We have not yet solved for y.
Directrix (directrix):
3 = x - 2
+2 +2
=========
What does x equal?
OpenStudy (anonymous):
5 o.o
Directrix (directrix):
Yes, x = 5.
Now, to get y.
AM = MC
3y - 2 = 2y + 4
Subtract 2y from both sides
y = 4 + 2
y = ?
OpenStudy (anonymous):
6
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