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Physics 12 Online
OpenStudy (anonymous):

I am currently stuck on a Coulombs Law problem in physics 2. Any advise would be of great help. The problem is posted in the image below.

OpenStudy (anonymous):

OpenStudy (abhisar):

@c_c_mill

OpenStudy (abhisar):

|dw:1420911935308:dw|

OpenStudy (abhisar):

Is the arrangement clear?

OpenStudy (anonymous):

Yes but it does not fit the one that is described in the problem.

OpenStudy (anonymous):

Q1 is at (0,3) Q2 at (0,-3) and Q3 at (4,0)

OpenStudy (abhisar):

So, where is the problem?

OpenStudy (abhisar):

oh yes!

OpenStudy (abhisar):

|dw:1420912329755:dw|

OpenStudy (abhisar):

ok?

OpenStudy (anonymous):

Okay yes I had something similar to this drawn. I calculated the force using a distance of five for both. I then used sin and cos to find my components and added them. I got the wrong answer. Could have been a mathematical error but I couldn't find it.

OpenStudy (anonymous):

I also tried changing the sign on the answer just to see and was still incorrect.

OpenStudy (abhisar):

Ok, let's see how to do it... #1 \(\sf Q_1\)=68 \(\sf Q_2=68 \\ Q_3=23\) Force for each of them will be equal to \(\sf \huge \frac{K\times 68 \times 23}{5^2}\)

OpenStudy (abhisar):

Correct?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

However I believe you must convert to standard units first.

OpenStudy (abhisar):

Now we need to find the cos component and for that we need to find the value of \(\sf Cos \theta\) |dw:1420913332904:dw|

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