Help? Fan and also Testimonial.
@Directrix
I get it but i just dont know what to put for an answer haha im all mixed up .-.
A rhombus has 4 congruent sides.
So, for the proof, that gives two sides of one triangle congruent to two sides of the other.
What side do the two triangles share?
@Here_to_Help15
They are congruent?
Sorry i am not very great at geometry :/
Look at the diagram.
There are two triangles.
yes i see
They share a side. They have a side in common.
Name that side.
BC=AD?
Look at the attached diagram. Which side is BOTH blue and green?
Oh lol i feel like a idiot 0.o A and C
Segment AC is the side they share. So, Segment AC is congruent to Segment AC will be a step in the proof. A segment is congruent to itself by the reflexive property.
Then, with the other two pairs of congruent sides, the triangles will be congruent by SSS Postulate. That is the gist of how the proof will go.
gist?
haha i just searched it up but thanks
2: the main point or part : essence <the gist of an argument>
Ok at the end of this post can you help me sum it up?
I will sum it up
you just tell me if im correct
Look in your text to see how a rhombus is defined. There are two or three different correct ways. But, how it is defined in your text will determine how the first step or two of the proof will go.
Is that all?
I need the definition from your text. Then, I'll write the steps and leave the reasons for you.
Oki lemme grab them
So, what is it? Look in the glossary.
It says a rhombus is a parallelogram with four congruent sides
Okay.
Oh and i see you have no mathlete or at least human calculator mind if i ask why?
Steps ==== 1.Quadrilateral ABCD is a rhombus 2. Seg AB ≅ Seg CD; Seg CB ≅ Seg AD 3. Seg AC ≅ Seg CA 4. Tri ABC ≅ Tri CDA
um whats those question marks thinga majig?
>> i see you have no mathlete or at least human calculator mind if i ask why? I did not unwrap them.
Now, it's your turn to get to work on the reasons.
@Here_to_Help15 If you post them here, I'll check them if you'd like that.
Ok thaks
All sides of a rhombus are equal in measure, so AB is congruent to AD and BC is congruent to DC. Then BD is congruent to BD by reflexive equality. Hence ABC is congruent to CDA by SSS.
That is close enough for government work.
goverment work?
government @@Directrix
Look it up. I'm helping you with vocab here.
lol
But how are you referring it to me?
At the beginning of your proof, you should establish that you are given a rhombus. Then, mention about the sides being equal in measure. The theorem you are proving is this: A diagonal of a rhombus divides the rhombus into two congruent triangles.
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