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Mathematics 12 Online
OpenStudy (studygurl14):

@surry99

OpenStudy (surry99):

I am here

OpenStudy (here_to_help15):

hi :D

OpenStudy (studygurl14):

Okay, hold on a sec while i get a question

OpenStudy (here_to_help15):

k

OpenStudy (studygurl14):

OpenStudy (surry99):

ok what do you understand about balancing equations?

OpenStudy (here_to_help15):

You mind if i help?

OpenStudy (studygurl14):

Not much. All I know is that the amount of atoms of each element has to be the same. You can help @Here_to_Help15 , just don't confuse me, hah. :)

OpenStudy (here_to_help15):

Ill do my best :D

OpenStudy (surry99):

two principles need to be obeyed in all balanced equations: 1) Conservation of mass 2) Conservation of Charge

OpenStudy (surry99):

are you aware of these principles?

OpenStudy (here_to_help15):

2Fe + 3Cl2 --> 2FeCl3 is your balanced equation. The coefficient for Cl2 is thus 3. Note: 2Fe + 3Cl2 --> 2FeCl3 Left side of the equation: 2 Fe 6 Cl Right side of the equation: 2 Fe 6 Cl, so your equation is balanced.

OpenStudy (here_to_help15):

If you need a different explanation i can try an easier way?

OpenStudy (studygurl14):

i know the conservation of mass, but not charge

OpenStudy (studygurl14):

@Here_to_Help15 when you explain you really need ot break it down and explain concepts of each step. or else it means nothing to me

OpenStudy (surry99):

Conservation of charge is just as important and becomes very important when we deal with things lile oxidation numbers

OpenStudy (surry99):

things like oxidation numbers

OpenStudy (here_to_help15):

Easiest way to do these is look at the half reactions: Fe ---> Fe+3 + 3e- Cl2 + 2e- --> 2 Cl- Now get the same number of electrons on both sides. To do this you need to multiply the first one by 2 and the last one by 3: 2 Fe ---> 2 Fe+3 + 6 e- 3 Cl2 + 6e- ---> 6 Cl- Add them together and you get a balanced equation: 2 Fe +3 CI2 ---> 2 FeCI3

OpenStudy (studygurl14):

oxidation numbers?

OpenStudy (surry99):

you do not need to know about them yet but lets go through your problem.

OpenStudy (studygurl14):

Okay

OpenStudy (surry99):

Fe + Cl2---> FeCl3 agreed

OpenStudy (studygurl14):

agreed

OpenStudy (surry99):

ok lets balance mass first... 1 Fe on left = 1 Fe on right...good 2 Cl on left but 3 Cl on right...hwat do you need to do to balance cl on both sides?

OpenStudy (studygurl14):

add another Cl

OpenStudy (studygurl14):

or...take one away

OpenStudy (surry99):

yes and we do that by changing the coefficients in front of the Cl2 and FeCl3.. what is the least common multiple of 2 and 3?

OpenStudy (studygurl14):

6

OpenStudy (surry99):

yes, so if you place a 3 in front of Cl on the left and a 2 in front of FeCl3 on the right then you will have 6 Cl on each side

OpenStudy (surry99):

go ahead and do that and tell me what happens to the Fe

OpenStudy (studygurl14):

Like this? 4Fe + 6Cl --> 2Fe2Cl3 ..?

OpenStudy (surry99):

not quite Fe + Cl2---> FeCl3 now put in the 3 in front of Cl2 and a 2 in front of FeCl3...remember we are changing the coefficients in the equation not the subscripts... So now Ihave: Fe + 3Cl2---> 2FeCl3 agreed

OpenStudy (studygurl14):

agreed

OpenStudy (surry99):

now what do we have to do to balance the Fe?

OpenStudy (studygurl14):

add one or take one away

OpenStudy (surry99):

Always thing in terms of adding only when you are balancing...

OpenStudy (studygurl14):

Okay

OpenStudy (surry99):

So how do you balance the Fe now ....remember only by adding

OpenStudy (studygurl14):

add one to the left side.

OpenStudy (surry99):

or in chemistry talk change the coefficient for Fe on the left from 1 to 2 go ahead

OpenStudy (studygurl14):

2Fe + 3Cl2 --> 2FeCl3

OpenStudy (surry99):

so far so good?

OpenStudy (studygurl14):

yep :)

OpenStudy (studygurl14):

so then the coefficent is 3, becaues that's what is in front of Cl2

OpenStudy (surry99):

Each species has its own coefficient: 2 For Fe 3 for Cl2 2 for FeCl3

OpenStudy (studygurl14):

I see. :) Could we try another one to make sure I get it? I have one from my chem book

OpenStudy (surry99):

yes but we are not quite done... Mass is now conserved... Lets check conservation of charge...if any of these chemical species had a real charge on them where would they appear in the symbol?

OpenStudy (studygurl14):

it would appear as a exponent. Well, nto really, but the same place

OpenStudy (surry99):

Exactly....do any of our species have charges?

OpenStudy (studygurl14):

no. They are all positive

OpenStudy (studygurl14):

soryr, neutral i mean

OpenStudy (surry99):

Yes they are all neutral so here is how we show charge is balanced... 2 mols of 0 charge from the iron + 3 mols of 0 charge form the Chlorine = 2 mols of 0 charge from the Iron(iii) chloride this may seem trivial at this stage but trust me you will need it later

OpenStudy (surry99):

go ahead and post another question please

OpenStudy (studygurl14):

balance the equation AgNO3 + H2S --> Ag2S + HNO3 That one looks complicated "/

OpenStudy (studygurl14):

:/

OpenStudy (surry99):

you see now your equation is balanced in mass and charge ...you are done!

OpenStudy (surry99):

ok, how many silvers on the left and right?

OpenStudy (studygurl14):

left: 1 right: 1

OpenStudy (surry99):

look at the right again

OpenStudy (studygurl14):

oh, wait. 2 (I was looking at S, not Ag)

OpenStudy (surry99):

ok so what do you put in front of the silver on the left?

OpenStudy (studygurl14):

2

OpenStudy (surry99):

go ahead and update the equation

OpenStudy (studygurl14):

2AgNO3 + H2S --> Ag2S + HNO3 but that affects the N and O, so we need to do more balancing. :)

OpenStudy (studygurl14):

2AgNO3 + H2S --> Ag2S + 2HNO3 !!! By jove, I think I got it. :)

OpenStudy (surry99):

yes...the NO3 is called nitrate... how many nitrates on the left and right?

OpenStudy (surry99):

yes you did...now show me that charge is balanced

OpenStudy (studygurl14):

Okay...that's tougher...let's see...

OpenStudy (surry99):

you can do it....do any of the species have a charge?

OpenStudy (studygurl14):

I don't know what to call the AgNO3...silver nitrate?

OpenStudy (studygurl14):

they are all neutral

OpenStudy (surry99):

yes

OpenStudy (studygurl14):

Okay, so.... 2 moles of 0 charge from the silver nitrate + 1 mole of 0 charge from the hydrogen sulfide = 1 mol of 0 charge from the silver sulfide + 2 moles of 0 charge from the hydrogen nitrate

OpenStudy (studygurl14):

(don't know if I have the right suffix there...-ide ?)

OpenStudy (surry99):

Excellent...hydrogen nitrate is acceptable

OpenStudy (studygurl14):

haha, "acceptable"...what else would it be called?

OpenStudy (surry99):

if it is dissolved in water , it is called nitric acid.

OpenStudy (surry99):

Want to do one more?

OpenStudy (surry99):

or different concept?

OpenStudy (studygurl14):

sure...um...how about this: Reqrite the word equation as balanced chemical equation hydrogen + sulfur --> hydrogen sullfide

OpenStudy (studygurl14):

i think that's what we just did, sort of, except backwards...the previous example had hydrogen sulfide in it...

OpenStudy (surry99):

go ahead...

OpenStudy (studygurl14):

H + S --> H2S 2H + S --> H2S ???

OpenStudy (surry99):

This is actually more complicated than it appears... there is hydrogen the element...H then there is hydrogen gas...H2

OpenStudy (surry99):

We often refer to what is called the "standard state" for a species...that means what is exists as at P = 1 atm and T = 298 K. For Hydrogen, it is H2 and for Sulfur it is S8 So the equation would be H2 + S8 ---> H2S go ahead and balance it please

OpenStudy (studygurl14):

ah...I see. H2 + S8 --> 8H2S 8H2 + S8 --> 8H2S ???

OpenStudy (surry99):

yes...the nice thing about balancing equations is you can always check them when you are done to make sure you did it correctly meaning: 1) mass must be conserved 2) charge must be conserved

OpenStudy (studygurl14):

True. Involves a lot of math

OpenStudy (surry99):

yes, but you love math!

OpenStudy (surry99):

and you will someday love chemistry too!

OpenStudy (surry99):

next up?

OpenStudy (studygurl14):

Haha, I'm good at math. I don't like it (well...most of the time...). xD

OpenStudy (studygurl14):

I'm going to link you to another thread

OpenStudy (surry99):

ok you cool with balancing now?

OpenStudy (studygurl14):

Yeah. Much better. THANK YOU! You are amazing

OpenStudy (studygurl14):

Thank you so much for doing this with me, a complete stranger. :)

OpenStudy (surry99):

ah...you are just a good student!

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