Question

help

Answer 1

Noor has money in a piggy bank. The amount
of money, A, in her piggy bank changes daily
and is related to the number of days, d, that
have passed since she started keeping track of
money in her bank.
(a)
Suppose Noor has $9.35 in her piggy bank
at the start and adds 50¢ per day. Write
a linear equation to represent how A is
related to d.
(b)
Identify the starting amount and savings
rate modeled by each equation.
A = 11.65 + 0.70d
A = 6.90 + 0.35d
(c)
Suppose that instead of adding 50¢ per day,
Noor takes out 50¢ per day. Write a new
linear equation to model this situation and
graph it

Answer 2

ok.
so:
A: f(x) = 9.35 + 50x

Answer 3

(a) The amount $9.35 represents the y-intercept,
and the amount 50¢ represents the slope of
the linear equation. Using the slope-intercept
form of a line and replacing y with A and x
with d, the linear equation is A = 0.50d + 9.35.
(b) For the equation A = 11.65 + 0.70d, the
starting amount is $11.65 and the savings
rate is 70¢/day. For the equation
A = 6.90 + 0.35d, the starting amount is $6.90
and the savings rate is 35¢/day.

Answer 4

found for a and b r thess right?

Answer 5

For B i would just graph it knowing that the dependent variables are the starting price...

Answer 6

(c) If Noah takes 50¢ out of the piggy bank each
day, the slope of the linear equation modeling
this situation would be −0.50. Since the piggy
bank originally contained $9.35, the linear
equation modeling this situation is
A = −0.50d + 9.35. To graph the linear equation,
find the d-intercept by replacing A with 0 and
solve for d: A = −0.50d + 9.35;
0 = −0.50d + 9.35;
0 − 9.35 = −0.50d + 9.35 − 9.35;
−9.35 = −0.50d; _− −_09_..53_05_ = −−_0_0.5._50_0d_ ; 18.7 = d.
The d-intercept is 18.7. Using the A-intercept of
9.35 and a d-intercept of 18.7, you can graph the
linear equation.