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OpenStudy (brucebaner):
OpenStudy (anonymous):
You can find the solution by substitution, it's already solved y for you, so let y = y and solve for x afterwards plug in the value of x in any of the equations to find the following y.
OpenStudy (anonymous):
\[y = \frac{ 3 }{ 2 }x\]
\[y = -\frac{ 1 }{ 2 }x+4\]
\[\frac{ 3 }{ 2 }x=-\frac{ 1 }{ 2 }x+4\] letting y = y, solve for x now.
OpenStudy (brucebaner):
kk
OpenStudy (brucebaner):
so can you help me do that plz
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OpenStudy (anonymous):
Give it an attempt and see what you get, and if you get stuck somewhere just ask then.
OpenStudy (brucebaner):
is it x=2 and y=3?
OpenStudy (brucebaner):
@iambatman
OpenStudy (anonymous):
That looks good!
OpenStudy (brucebaner):
so im correct thx so much @iambatman
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OpenStudy (anonymous):
\[(x,y) \implies (2,3)\] yup :)
OpenStudy (texaschic101):
3/2x = -1/2x + 4 --- if you want to get rid of the fractions, multiply entire equation by 2
3x = -x + 8 -- add x from both sides
3x + x = 8
4x = 8
x = 2
-1/2x + 4 = - 1/2(2) + 4 = - 1 + 4 = 3
yep...x = 2 and y = 3