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Mathematics 19 Online
OpenStudy (brucebaner):

help me @Directrix

OpenStudy (brucebaner):

OpenStudy (anonymous):

You can find the solution by substitution, it's already solved y for you, so let y = y and solve for x afterwards plug in the value of x in any of the equations to find the following y.

OpenStudy (anonymous):

\[y = \frac{ 3 }{ 2 }x\] \[y = -\frac{ 1 }{ 2 }x+4\] \[\frac{ 3 }{ 2 }x=-\frac{ 1 }{ 2 }x+4\] letting y = y, solve for x now.

OpenStudy (brucebaner):

kk

OpenStudy (brucebaner):

so can you help me do that plz

OpenStudy (anonymous):

Give it an attempt and see what you get, and if you get stuck somewhere just ask then.

OpenStudy (brucebaner):

is it x=2 and y=3?

OpenStudy (brucebaner):

@iambatman

OpenStudy (anonymous):

That looks good!

OpenStudy (brucebaner):

so im correct thx so much @iambatman

OpenStudy (anonymous):

\[(x,y) \implies (2,3)\] yup :)

OpenStudy (texaschic101):

3/2x = -1/2x + 4 --- if you want to get rid of the fractions, multiply entire equation by 2 3x = -x + 8 -- add x from both sides 3x + x = 8 4x = 8 x = 2 -1/2x + 4 = - 1/2(2) + 4 = - 1 + 4 = 3 yep...x = 2 and y = 3

OpenStudy (luckycoins888):

yep

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