Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (albert0898):

Please explain how to do this. http://imgur.com/AiAdCPF

OpenStudy (danjs):

In other words this is what it is \[\frac{ \frac{ 1 }{ x }+1 }{ x+1 }\]

OpenStudy (danjs):

x^-1 = 1/x , in the first term in the numerator

OpenStudy (danjs):

now what you can do is multiply the fraction by \[\frac{ x }{ x }\]

OpenStudy (danjs):

\[\frac{ \frac{ 1 }{ x }+1 }{ x+1 }*\frac{ x }{ x }\] what does that give ya?

OpenStudy (albert0898):

1 + x / (x^2) + x

OpenStudy (albert0898):

@DanJS

OpenStudy (danjs):

yes, factor an x from the denominator, and cancel , done

OpenStudy (albert0898):

The answer is \[\frac{ 1 }{ x }\] . By factoring an x from the denominator, the answer would then be \[\frac{ 1 + x }{ x }\] which is wrong. @DanJS

OpenStudy (danjs):

\[\frac{ 1 + x }{ x^2+x } = \frac{ x + 1 }{ x(x+1) } = \frac{ 1 }{ x }\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!