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Please explain how to do this. http://imgur.com/AiAdCPF
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In other words this is what it is \[\frac{ \frac{ 1 }{ x }+1 }{ x+1 }\]
x^-1 = 1/x , in the first term in the numerator
now what you can do is multiply the fraction by \[\frac{ x }{ x }\]
\[\frac{ \frac{ 1 }{ x }+1 }{ x+1 }*\frac{ x }{ x }\] what does that give ya?
1 + x / (x^2) + x
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@DanJS
yes, factor an x from the denominator, and cancel , done
The answer is \[\frac{ 1 }{ x }\] . By factoring an x from the denominator, the answer would then be \[\frac{ 1 + x }{ x }\] which is wrong. @DanJS
\[\frac{ 1 + x }{ x^2+x } = \frac{ x + 1 }{ x(x+1) } = \frac{ 1 }{ x }\]
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