Question

simplify the complex fraction

Answer 1

@Jhannybean hey! could you help out with this one as well?

Answer 2

get rid of the compound fraction
see what happens if you multiply by the least common multiply of the bottoms
the bottoms are: 4y, y, y, 2y
so the lcm is 4y
so multiply the top and bottom by 4y

Answer 3

let me know what you get as a result

Answer 4

do i just multiply each fraction seperately then? would that leave 3-8 on the top?

Answer 5

yes you are multiply top and bottom by 4y
so on top you would have 3-8

Answer 6

okay and then on the bottom it would be 4+12/8?

Answer 7

we already did a similar problem!?

Answer 8

hmm how did you get the 12/8?

Answer 9

i know!! i just get so jumbled up, im just practicing as many as i can.

Answer 10

i canceled out the y and multiplied the top and bottom by 4

Answer 11

but that isnt right is it hahah

Answer 12

well first try your hardest before you post it! if you just post and you don't look back at the problem we did, you won't catch it in good way

Answer 13

Multiply both top and bottom by \(\dfrac{y}{y}\) remember?

Answer 14

i did, but i need to do it dozens of times until i understand it. especially with questions like these where they look different.

Answer 15

\[\frac{\frac{3}{4y}-\frac{2}{y}}{\frac{1}{y}+\frac{3}{2y}} \cdot \frac{4y}{4y} =\frac{4y(\frac{3}{4y}-\frac{2}{y})}{4y(\frac{1}{y}+\frac{3}{2y})} \\ \frac{4y(\frac{3}{4y})-4y(\frac{2}{y})}{4y(\frac{1}{y})+4y(\frac{3}{2y})} \\ \frac{\frac{4y}{4y} 3-\frac{y}{y}4(2)}{\frac{y}{y}4+\frac{4y}{2y}(3)} \\ \]

Answer 16

try your simplication of this again

Answer 17

I don't you reduced 4/2 *3 correctly

Answer 18

okay so its 3-8/4+6?

Answer 19

\[\frac{\dfrac{3}{4y}-\dfrac{2}{y}}{\dfrac{1}{y} + \dfrac{3}{2y}}\cdot \frac{4y}{2y}\] You can also do that.

Answer 20

yes (3-8)/(4+6)

Answer 21

dang.. @freckles is a fast typer lol.

Answer 22

ah okay thank you! im writing it all down i just need to start remembering it! so my final answer is 1/2

Answer 23

@Jhannybean the denominator in your simplification would be
2+3

Answer 24

-1/2**

Answer 25

i think you are off by a sign @sammyjpod

Answer 26

oh nvm

Answer 27

you fixed it :p

Answer 28

\[=\frac{3-(2\cdot 4)}{(1\cdot 2) +3}\]@xapproachesinfinity Thanks, I realized that, hence I deleted it :P

Answer 29

haha yeah i caught that too! thanks.

Answer 30

:)

Answer 31

can you get rid of the compound fraction here:
\[\frac{\frac{a}{b}+\frac{c}{d}}{\frac{m}{n}+\frac{r}{s}}\]

Answer 32

hmmm how could i if there aren't any same denominators?

Answer 33

well then the lcm would be bdns

Answer 34

and you would multiply top and bottom by that

Answer 35

oh okay yeah.

Answer 36

finding LCM and factoring are where i struggle the most.

Answer 37

\[\frac{\frac{a}{b}+\frac{c}{d}}{\frac{m}{n}+\frac{r}{s}} \cdot \frac{bdns}{bdns} \\ \frac{\frac{a}{b}bdns+\frac{c}{d}bdns}{\frac{m}{n} bdns+\frac{r}{s} bdns} \]
\[\frac{ \frac{a}{\cancel{b} } \cancel{b} dns+\frac{c}{\cancel{d}} b \cancel{d} ns}{\frac{m}{\cancel{n}} bd \cancel{n} s+\frac{r}{\cancel{s}} bdn\cancel{s}}\]

Answer 38

\[\frac{a dns+cbns}{mbds+rbdn}\]