Question

Question 2.2. Which ordered pair makes the inequality true?

2x + y > 8
(Points : 1)
(–13, 0)
(–2, 13)
(0, 4)
(5, –3)

Answer 1

Best way would be evaluate Left hand side and right hand side of the inequality for each option.

Answer 2

I will give you an example:

Take the first option -> (-13,0):

LHS = 2x + y

Now, here x = -13 and y = 0

So:

2x + y = 2(-13) + 0 = -26

RHS = 8

Now, is -26 > 8 ?

NO!!!

So, this pair does NOT make the inequality true.

Answer 3

Similarly, you can try for other options.

Answer 4

Can you tell me which would be the correct answer ?

Answer 5

umm...(5,-3) ? Ah i suck at math lol

Answer 6

@vishweshshrimali5 am I wrong?

Answer 7

Yeah :(

See for (5,-3):

2y + x = (2 * 5) - 3 = 10 - 3 = 7

Now, is 7 > 8 ?

NO !!

Answer 8

Try again :)

Answer 9

(0,4)?

Answer 10

What is (2x+y) for (0,4) ?

Answer 11

x = 0 and y = 4

Answer 12

x=-2y-1+-0.5y? that's what I got idk i have a hard time with stuff like this

Answer 13

am I wrong again @vishweshshrimali5 ?

Answer 14

See:

Lets not make it too difficult.

We have:

LHS = 2x + y

y = 4 and x = 0

Now 2x + y = 2 * 0 + 4 = 4

Now 4 is NOT greater than 8

So, this is NOT the correct option

Answer 15

so, then the only option left is (-2,13)

Answer 16

What is 2x + y for (-2,13)?

x =-2 and y = 13

So:

2x + y = 2 * (-2) + 13 = -4 + 13 = 9

which is surely greater than 8

So, this is the correct answer