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@Jhannybean
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Why do you close your questions? :P
for this one i got 16/3
\[v(t) = -t^2+4 = 0 \implies t^2 = 4 \implies t = \pm 2 \]So... have any idea how to find the position function? :)
oh wat i set it up wrong, one sec lt me redo it
Haha, ok.
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With what you have given me, you would find the position function by integrating the velocity function.
\[s(t) = \int v(t)dt\]
16 (:
Im not understanding what "16" means.
16 ft is the distance
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And can you explain to me what you did to get that?
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