Ask your own question, for FREE!
Organic 16 Online
OpenStudy (kainui):

I'm going to try to visit the organic chemistry section more often in order to help others enjoy organic synthesis and really focus on understanding reaction mechanisms and problem solving since it's fun! I'll just start some conversation here and feel free to talk about anything OChem related here! =D

OpenStudy (kainui):

Here's a fun thing to notice. Whenever you try to identify if a molecule is aromatic or not, you have to check if it has a Huckel number of pi electrons, which follow the pattern 4n+2, which can be simply listed as 2, 6, 10, 14, 18, 22, etc... (notice benzene has 6 pi electrons, so it's second on the list.) But is there an easier way? Yes! If they only contain carbon and hydrogen we can make a much simpler and special rule! Every time you see pi electrons, they will always come in pairs and specifically in hydrocarbons they will only appear as double or triple bonds. That means we can see that for every 2 pi electrons there is 1 double bond. So instead of counting 4n+2 pi electrons, we can factor out a 2 to get 2n+1 leftover! 2n+1 is just all odd numbers! So instead of looking for 4n+2 pi electrons, you can just count up the number of double bonds. If there is an odd number of them, then it can be aromatic!

OpenStudy (abb0t):

What about: |dw:1420863245328:dw|

OpenStudy (kainui):

Oh I thought I said it only works with neutral hydrocarbons but I guess I left that out. I think I deleted it cause it was getting too long with a discussion about cyclopentadiene and I decided to toss that out cause it was getting too wordy haha.

Nnesha (nnesha):

that's good chemistry, organic chemistry one of my favorite subject but i didn't get the chance to take it at school :( organic structures bond line structrues are m favorite topic :DD:D:D:D:D:D ---> http://secure.tutorsglobe.com/CMSImages/240_Orgnaic_Chemistry_homework_Help.gif v ^^^^^^^^^^^^6like this

OpenStudy (abb0t):

Too complex.

Nnesha (nnesha):

what..........?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!