Question

Math 30 Trigonometry

Answer 1

grade twelve math

Answer 2

but anyways heres the question

Answer 3

Canadian? :D

Answer 4

Did you find a bat signal?

Answer 5

So it says to determine the general solution for sinx=0

so the solutions are 0 (degrees), 180, and 360 (all in degrees)

so I would have three general solution being 360n, 180+360n, and 360+360n

Okay so these are correct but they said that it could be combined together to get one solution which would be 180n? howw in the world ??

and yes canadian

Answer 6

what is the range for your sine function?

Answer 7

I mean interval

Answer 8

as in period?

Answer 9

i.e is it from \((0 \le x \le \dfrac{\pi}{2})\) or is it from \((0 \le x \le 2\pi)\)?

Answer 10

\[0 \le x \le 360\] assuming

Answer 11

oh, yeah well it doesnt say in the question

Answer 12

\[\sin(x)=0\]\[\sin^{-1}(\sin(x)) = \sin^{-1}(0)\]\[x=\sin^{-1}(0)\]

Answer 13

\[\sin(x+2\pi) = 0\]\[\sin^{-1}(\sin(x+2\pi)) = \sin^{-1}(0)\]\[x+2\pi = \sin^{-1}(0)\] I think this would be the proper way of going about solving it..

I'm actually terrible with these. :|

Answer 14

Mmm I just don't get how the combining of the three works to get 180n...

Answer 15

Here, just make sure you realize what 180n means. It means n is any integer (positive and negative whole numbers both) so try plugging in a few values and we have: \[\Large 180 * 0 =0 \\ \Large 180 * 1 = 180 \\ \Large 180 * 2 = 360 \\ ...\] There are actually infinitely many, and this makes sense, a sine curve continuously wiggles over the x-axis! =D

Answer 16

with the graph we can see the general solution is \[xn \pi, n \in Z\] right? So this would give you all your general solutions, and I think your problem maybe asking for specific solutions where then you let n be an integer and plug in numbers.