A ball is thrown horizontally from the top of
a building 21.8 m high. The ball strikes the
ground at a point 101 m from the base of the
building.
The acceleration of gravity is 9.8 m/s
2
.
Find the time the ball is in motion.

Question

A ball is thrown horizontally from the top of
a building 21.8 m high. The ball strikes the
ground at a point 101 m from the base of the
building.
The acceleration of gravity is 9.8 m/s
2
.
Find the time the ball is in motion.

abhisar · Answer

Have you tried it first yourself?

anonymous · Answer

yes iv tryed but it keeps telling e it wrong

abhisar · Answer

Can you temme how are you doing it so that i could correct you....

anonymous · Answer

i did t= square root of (21.8/9.80

abhisar · Answer

Since,, the ball is thrown horizontally. The vertical component of initial velocity will be zero....ryt?

abhisar · Answer

Time of flight in this case will be equal to the time taken by a ball to reach the ground from 21.8 m during a free fall.

Use the equation $\sf s=ut+\frac{1}{2}\times g\times t^2$

take s=21.8
u=0 (initial velocity is 0 in case of free fall)
g=9.8$\approx$10

Calculate t

anonymous · Answer

ok thank you

abhisar · Answer

Welcome.