Question

An 11.2 g bullet leaves the muzzle of a rifle
with a speed of 408.3 m/s.
What constant force is exerted on the bullet
while it is traveling down the 0.6 m length of
the barrel of the rifle?
Answer in units of N

Answer 1

for the first one
you'll need to know F=ma
to solve for the constant force
but take note, you are given the speed not acceleration
so you still have to solve for acceleration
Use the ffg formula

\(V_f^2 - V_o^2 = 2as\)

where

Vf = velocity of the bullet as it leaves the muzzle = 408.3 m/sec (given)
Vo = initial velocity of bullet = 0
a = acceleration of bullet
s = length of the rifle's barrel =0.6 m

after calculating for acceleration, substitute the value into the formual F=ma and solve for the force

Answer 2

Thank you for the help I tried all of this and got the wrong answer is there anyway you could write out the work with the answer so I could see what I did wrong?

Answer 3

can you show me your work instead? I'll just check your solution if it's right

Answer 4

given:
m= 11.2 g
Vf= 408.3 m/s

F=ma = 11.2 a

solve for a:
\(V_f^2−V_o^2=2as\\(408.3)^2-0=2a(0.6)\\ \Large a=\frac{(408.3)^2}{2(0.6)}\)

what did you get for a?

Answer 5

@Joeyray still there?