can anyone break down the steps in this problem, so I can understand it. Solve for x.

log24 – log4x = 0
a.54
b.16
c. 6
d.36

Question

can anyone break down the steps in this problem, so I can understand it. Solve for x.


log24 – log4x = 0
a.54
b.16
c. 6
d.36

anonymous · Answer

Do either of these have abnormal bases?

anonymous · Answer

do you mean the 24?

anonymous · Answer

yeah, is it log base 2, log base 24, or is it just log(24)-log(4x)?

anonymous · Answer

it is the third one you wrote

anonymous · Answer

okay, give me just a sec to write this out.

anonymous · Answer

So what you're going to do is cancel out the log part of the expression. To do this, make each part of the equation an exponent to the number 10. You make it an exponent of 10 because log has a base of 10. Like this: $$10^{\log(24)}-10^{\log(4x)}$$ This makes the equation a simple 24-4x=0 and then you just solve for x. $$-4x=-24$$$$x=-24\div-4$$$$x=6$$ Does this answer your question?

anonymous · Answer

yes thank you so much.. I have been following my lessons and I just got lost this really helped (:

anonymous · Answer

You're welcome :)