simplify 1/9 - 1/x all over 1/81 - 1/x^2
9x/ (x + 9)
thanks!! but could you tell me how you got that?
The common denominator for the first two fractions is 9x. x/9x - 9/9x which would give you: (x-9)/9x For the second pair of fractions, your common denominator is 81x^2 x^2/81x^2 - 81/81x^2 which would give you (x^2 - 81)/81x^2 Set up the division: (x-9)/9x ÷ (x^2 - 81)/81x^2 When dividing fractions, you change the division sign to multiplication and invert the second fraction {(x-9)/9x} * {81x^2 / (x^2 - 81) } = {(x-9)/9x} * {81x^2 / (x - 9) (x + 9) } Now you can cancel the (x-9) on top and bottom: 81x^2 / { 9x (x + 9)} Reduce the top and bottom by 9x to get: 9x / (x+9)
thanks!! could you help with another one?
yeah close this ans start another
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