Simplify. (screenshot below)
k do u know what to do first @Sparklestaraa ?
\[7\sqrt{3}-4\sqrt{6}+\sqrt{8\cdot 6} -\sqrt{9\cdot 6}\]
\[8 = 2^3~,~ 9 = 3^2\]
For every pair of numbers under a square root, 1 comes out.
\[7\sqrt{3}-4\sqrt{6}+\sqrt{8\cdot 6} -\sqrt{9\cdot 6}\]\[=7\sqrt{3} -4\sqrt{6} +\sqrt{2^2 \cdot 2 \cdot 6} - \sqrt{3^2 \cdot 6}\]\[=7\sqrt{3} -4\sqrt{6} +2\sqrt{12} - 3\sqrt{6}\]\[=7\sqrt{3} - 4\sqrt{6} +2\sqrt{2^2 \cdot 3} -3\sqrt{6}\]\[=7\sqrt{3}-4\sqrt{6}+4\sqrt{3}-3\sqrt{6}\]Combine like terms. \[=\color{red}{7\sqrt{3}}\color{blue}{-4\sqrt{6}}\color{red}{+4\sqrt{3}} \color{blue}{-3\sqrt{6}}\]
I'm still honestly a little confused @Jhannybean
@fatZak
leave the\[7\sqrt{6}-4\sqrt{6}\] you cannot simplefied them any further
-3\[-3\sqrt{9}\]
come to this two part, first the\[\sqrt{48}\] which two numbers when multiplyh will give you 42 and one is a perfect square
3 and 16
3 x 16 =48
\[\sqrt{16}\times \sqrt{3}\]
\[\sqrt{16}=4\] so now \[\sqrt{48}= 4\sqrt{3}\]
see thats my problem thats not even a choice
i think i just have to simplify not solve
my choices are in the pic above
lets go to the \[\sqrt{54}\] 9*6=54 \[\sqrt{9}\times \sqrt{6}\]\[\sqrt{9}=3\]\[\sqrt{9}\times \sqrt{6}=3\sqrt{6}\]
wallah im so confused
now we have \[7\sqrt{3}-4\sqrt{6}+4\sqrt{3}-3\sqrt{6}\]\[11\sqrt{3}-7\sqrt{6}\]
ok
If you simplified my expression you would have gotten the same answer.
\(\color{blue}{\text{Originally Posted by}}\) @Jhannybean \[7\sqrt{3}-4\sqrt{6}+\sqrt{8\cdot 6} -\sqrt{9\cdot 6}\]\[=7\sqrt{3} -4\sqrt{6} +\sqrt{2^2 \cdot 2 \cdot 6} - \sqrt{3^2 \cdot 6}\]\[=7\sqrt{3} -4\sqrt{6} +2\sqrt{12} - 3\sqrt{6}\]\[=7\sqrt{3} - 4\sqrt{6} +2\sqrt{2^2 \cdot 3} -3\sqrt{6}\]\[=7\sqrt{3}-4\sqrt{6}+4\sqrt{3}-3\sqrt{6}\]Combine like terms. \[=\color{red}{7\sqrt{3}}\color{blue}{-4\sqrt{6}}\color{red}{+4\sqrt{3}} \color{blue}{-3\sqrt{6}}\] \(\color{blue}{\text{End of Quote}}\) \[(-4-3)\sqrt{6} +(7+4)\sqrt{3} = -7\sqrt{6} +11\sqrt{3} \]
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