Question

exact diff. equations

Answer 1

What are we supposed to do? solve?

Answer 2

yes..

Answer 3

I think it is y =x, dat sit

Answer 4

I checked the exactness of the equation.

Answer 5

Isn't the exact answer |x| = |y|?

Answer 6

hehehe... I skip that step; However, since it solvable, it is exact

Answer 7

how did you solve this? i just don't get it. Haha

Answer 8

\(\dfrac{ydx-xdy}{x^2} =\dfrac{ydx}{x^2}-\dfrac{1}{x}dy=0 \)

Answer 9

\(\dfrac{ydx}{x^2}=\dfrac{dy}{x}\)
\(\dfrac{xdx}{x^2}=\dfrac{dy}{y}\)
\(\dfrac{dx}{x}=\dfrac{dy}{y}\)
hence x =y
dat sit

Answer 10

yes i got that

Answer 11

oh okay then integrate

Answer 12

I don't think we need integrate

Answer 13

someone said |x|=|y|, but why??? lnx = ln y, is it not that x, y > 0

Answer 14

However, more formal, we need y = x+ C

Answer 15

yes.. so we really need to integrate

Answer 16

hehehe... yes