Question

Which statement is true about the product

Answer 1

@misty1212

Answer 2

is this
\[\sqrt2(3\sqrt2+\sqrt{18})\]?

Answer 3

looks kind of weird, but if so when you multiply you get
\[3\times 2+\sqrt{36}=6+6\]

Answer 4

Distribute the square root of two and then simplify.

Answer 5

The answer would be "It is rational and equal to 12." This is due to the breakup of the problem that follows:

\[\sqrt{2}(3\sqrt{2}+\sqrt{18})\]
\[\sqrt{2}(3\sqrt{2}+\sqrt{9*2})\]
\[\sqrt{2}(3\sqrt{2}+3\sqrt{2})\]
\[\sqrt{2}(6\sqrt{2})\]
\[6*2 = 12\]

Answer 6

It's basically just like any other distributing equation, except you have square roots.