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Mathematics 13 Online
OpenStudy (anonymous):

A toy rocket is launched upward from ground level with an initial velocity of 42 meters per second. Its height is a function of time, given by h=-4.9^2+42t, where h represents the height in meters and t represents the time in seconds. a. The maximum height reached by the rocket is? b. The minimum height reached by the rocket is?

OpenStudy (danjs):

when the velocity equals zero

OpenStudy (anonymous):

i swear i just answered this question honest

OpenStudy (danjs):

^ happens all the time, should be an archive of all the questions with an easy search feature

OpenStudy (danjs):

Find \[\frac{ dh }{ dt }=0\] that time t, is where the velocity is zero, use that in the h(t) given function to get the height at that time t.

OpenStudy (anonymous):

answered it without calc too, just using the vertex is all

OpenStudy (danjs):

right, it is a parabolic path, maximum height is at the vertex , if you want to do it that way too

OpenStudy (anonymous):

I really can't figure it out can you tell me the maximum? ill give you a medal

OpenStudy (anonymous):

plug in \(\frac{30}{7}\) in to the equation for \(t\) or else cheat, i will show you how

OpenStudy (anonymous):

scroll down to where it says "maximum" you will see it is 90 http://www.wolframalpha.com/input/?i=-4.9x^2%2B42x

OpenStudy (anonymous):

thanks

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