A toy rocket is launched upward from ground level with an initial velocity of 42 meters per second. Its height is a function of time, given by h=-4.9^2+42t, where h represents the height in meters and t represents the time in seconds. a. The maximum height reached by the rocket is? b. The minimum height reached by the rocket is?
when the velocity equals zero
i swear i just answered this question honest
^ happens all the time, should be an archive of all the questions with an easy search feature
Find \[\frac{ dh }{ dt }=0\] that time t, is where the velocity is zero, use that in the h(t) given function to get the height at that time t.
answered it without calc too, just using the vertex is all
right, it is a parabolic path, maximum height is at the vertex , if you want to do it that way too
I really can't figure it out can you tell me the maximum? ill give you a medal
plug in \(\frac{30}{7}\) in to the equation for \(t\) or else cheat, i will show you how
scroll down to where it says "maximum" you will see it is 90 http://www.wolframalpha.com/input/?i=-4.9x^2%2B42x
thanks
Join our real-time social learning platform and learn together with your friends!