Question

Solving Radical Functions??

Answer 1

\[\frac{ 2x-5 }{ x-3 }-2=\frac{ 3 }{ x+3 }\]

Answer 2

and \[\frac{ 2 }{ x+2 }+\frac{ 1 }{ x-2 }=\frac{ 13 }{ }\]

Answer 3

First Equation:

Please, whta is the least common multiple?

Answer 4

oops...what is the least common multiple?

Answer 5

See, that's where I get stuck.. Since one is positive and one is negative, I don't know how to find the LCM

Answer 6

L.C.M of 6 and 7=6*7

Answer 7

42

Answer 8

\[\frac{ 2x-5 }{ x-3 }-2=\frac{ 3 }{ x+3 }\]
\[\frac{ 2x-5-2(x-3) }{ x-3 }=\frac{ 3 }{ x+3 }\]
\[\frac{ 2x-5-2x+6 }{ x-3 }=\frac{ 3 }{ x+3 }\]
\[\frac{ 1 }{ x-3 }=\frac{ 3 }{ x+3 }\]
cross multiply
3(x-3)=1(x+3)
3x-9=x+3
3x-x=3+9
2x=12
x=?

Answer 9

6! Thank you so much!!I think I get it now!

Answer 10

Can you help me with the second one? I kinda got it but I'm confused on how to do it when the third denominator is 21. Please and thank you!

Answer 11

i do not see 21 anywhere written.

Answer 12

\[\frac{ 2 }{ x+2 }+\frac{ 1 }{ x-2 }=\frac{ 2\left( x-2 \right)+1\left( x+2 \right) }{ \left( x+2 \right)\left( x-2 \right) }=\frac{ 2x-4+x+2 }{x^2-2^2 }=\frac{ 3x-2 }{ x^2-4 }\]
now you can solve further.

Answer 13

There is a 21 supposed to be under the 18 whops sorry