ODE question again. So I need to determine for what r values the ode has a solution of the form \(y=t^r\) for t>0. What method yields only \(t^r\)? I know ce^rt, but not one for t and cannot locate it in the book.
@ganeshie8 @Marki
the actual problem, I can do, but I would use an integrating factor for this problem not whatever method this is
so for matrices or equations ?
it's an equation, specifically:\[y''+4t^{-1}y'+2t^{-2}y=0\]
I am assuming there is some method similar to the characteristic eq. then solve for r and have a generic answer
this is special equation is it of Legendre or Bessel i dont memorize these stuff ;-;
no clue, We haven't learned it. This is something for the first week's homework...
ok i wanna refresh m mind what topics u have for the HW ?
uhm, well a lot there is like 50 problems, so first was, convert to canonical form, second verify something is the solution of the de, third determine r values which give an answer of ce^rt, fourth, this stuff with the t^r, fifth all of the numerical methods, sixth translate the dif eq tot he origin, seventh method of successive approximations, eighth sequence convergence(idk i haven't tried those yet)
ok i'll try something with Bessel
ok, and can you link to something, I've never heard of him
check equation 2 http://mathworld.wolfram.com/BesselDifferentialEquation.html
interesting @wio
sowe should convert ur equation to this form \(y''+t^{-1}y'+(1-n^2y^{-2})y=0\)
I like to guess, because I've forgotten a lot\[ y=t^{r}\\ y' = rt^{r-1}\\y'' = r(r-1)t^{r-2} \]And then: \[ r(r-1)t^{r-2} +(4t^{-1})rt^{r-1} + (2t^{-2})t^r=0 \]
@Marki that seems a little complicated, this is the first week... I would need some explanations in english. I'm a little confused by the terminology. @wio cool it looks like a derivation
ok then forget it :P this is the only way i remember tbh for this equation idk maybe @ganeshie8 could also know
Hmm....\[ \bigg(r(r-1)+4r+2\bigg)t^{r-2} = 0t^{r-2}\implies r^2+3r+2=0 \]
lol it's cool,
so I guess to use that we would need an n, and to +1 and -1?
Now we can verify whatever solution we get.
@wio, I like your work, but I am confused a little let me reread it
ok, so that is awesome wio! I get it! and I think it will work perfectly!
What is the method you are supposed to be using?
no clue
lol that's the issue
the only thing similar is the method where you solve the char eq then have a solution of the form ce^rt, but the book doesn't really cover that either
this teacher is sort of a discombobulated, barely speaks english mess
Are you supposed to put it in canonical form?
lol I wish, but no not on this one. That would have been much simpler
Okay, I think that doing what I did is the answer then?
if it helps the original eq is this, \[t^2y''+4ty'+2y=0\]
I think it's possible
I have convinced myself that you are 100% correct wio, thanks, really really great reasoning skills!!!
ok here is wolfram solution
but term of x instead of t xD save it u might use it some where xd
that's awesome, it is wio's method!
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