Question

i need help with a math problem What is the quotient in simplified form? State any restrictions on the variable. Show
Work.

Answer 1

please help

Answer 2

ok first factor a^2-8a+15

Answer 3

how ?

Answer 4

ok if this is algebra then look up factoring polynomials

Answer 5

and then apply the same rule into the equation

Answer 6

ok and yeah its algebra 2

Answer 7

gimme two numbers that multiply to equal 15 and add to equal -8

Answer 8

4 and 5

Answer 9

no, because 4 x 5 is 20

Answer 10

-3 and -5 but i would recommed to lear the polyomials is very useful

Answer 11

i know

Answer 12

i meant to put 3

Answer 13

Im on the same level as you so I know the cofusion

Answer 14

ok, yes correct, -3 and -5 are the asnwers

Answer 15

therefore, -3 and -5 are the roots of the polynomial a^2-8a+15

Answer 16

ok

Answer 17

and since this is true, we can factor the polynomial such that a^2-8a+15=(a-(3))x(a-(5)) or (a-3)(a-5)

Answer 18

and i was incorrect about that roots thing, -3 and -5 are NOT the roots, 3 and 5 are the roots

Answer 19

but it factors to (a-3)(a-5)

Answer 20

ohh ok

Answer 21

now we can rewrite the problem as \[\frac{ a+2 }{ a-5 }\div \frac{ a+1 }{ (a-3)(a-5) }\]

Answer 22

but.... since we are dividing fractions, we can flip the second and change the\[\frac{ a+2 }{ a-5 }\times \frac{ (a-3)(a-5) }{ a+1 }\] sign to multipication: like so

Answer 23

do you know what we can do from here?

Answer 24

no

Answer 25

we simplify

Answer 26

yea, we simplify by eliminating the term (a-5)

Answer 27

when we do this, we get \[\frac{ a+2 }{ 1 }\times \frac{ a-3 }{ a+1 }\]

Answer 28

ok can you help me with that please:)

Answer 29

In fully simplified form, this is \[\frac{ (a+2)(a-3) }{ a+1 }\]

Answer 30

and now for the restrictions

Answer 31

do you know about restrictions?

Answer 32

no

Answer 33

plz just help me or just put the answer

Answer 34

ok then, since all of these cannot be 0: (a+1), (a-3), (a-5), a cannot be -1, 3, or 5
please medal me ;)

Answer 35

lol thanks :)

Answer 36

np