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Mathematics 15 Online
OpenStudy (anonymous):

What is the applied force needed to move a 50.0kg suitcase at a constant velocity horizontally across the floor if the coefficient of kinetic friction is 0.700? ***not sure!! :( thank you!! :D

OpenStudy (danjs):

Constant velocity, no acceleration. The applied force will equal the friction force in opposite direction.

OpenStudy (anonymous):

oh, so it would be 0.700 ? the applied force needed to move the suitcase? :/

OpenStudy (danjs):

no that is the coefficient of kinetic friction, you have to find the force from friction

OpenStudy (anonymous):

ohh okay! how do we do that? find the force from friction? :O

OpenStudy (anonymous):

@DanJS ?

OpenStudy (danjs):

i dont remember, normal force x something

OpenStudy (anonymous):

could we use f=m*a?

OpenStudy (anonymous):

:/

OpenStudy (danjs):

kinetic coefficient times the normal force = Force of the friction

OpenStudy (anonymous):

ohh okay so 0.700 * x = 50 ? solve for x? x=71.429 ?

OpenStudy (danjs):

|dw:1421014006870:dw|

OpenStudy (anonymous):

ohh what do we do from here? :O

OpenStudy (mathstudent55):

50 kg is a mass that needs to be converted to a weight.

OpenStudy (danjs):

The force applied = Force of friction, Force of friction = coefficient * Normal Force Normal Force = Mass*Gravity

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