please help medal and fan For the following system, if you isolated x in the first equation to use the Substitution Method, what expression would you substitute into the second equation? -x + 2y = -6 3x + y = 8
-2y + 6 2y - 6 2y + 6 -2y - 6
do u jst need to solve using subsitution?
yes
with these 2y - 6 2y + 6 -2y - 6
u there
yes...confused though
so am I do u know any one that can help
@TheSmartOne PLEASE help
do u understand this
u there
@mathmate please help
I got to leave sorry. But @mathmate @sleepyjess @pooja195 might be able to help you.
thank you
do u understand this
Given: -x + 2y = -6 3x + y = 8 From first equation: -x + 2y = -6 2y+6=x or \(\color{red}{x}=\color{red}{(2y+6)}\) Substitute into second equation: \(3(\color{red}{2y+6} )+ y = 8\) Distribute the multiplication by 3 and solve for y.
so it would be 6y+18+y=8?
Yes, so far so good!
ok now what do I do
@mathmate
Isolate y on the left, and numbers on the right, and solve for y. Y will be a fraction, but just keep going.
so it would u combine like terms to
To isolate y, you need to first add together the like terms of y: 6y+18+y=8 becomes 7y+18=8 Can you continue?
yes ok so it would then be 18=8-7y
If I were you, I would keep the 7y on the left, but subtract 18 from both sides. You want to keep variables on the left, and numbers on the right. 7y+18=8 subtract 18 from both sides 7y+18-18=8-18 Can you continue?
ok so it would be 7y=-10 and no
Don't worry, as I said, the answer for y will not be a whole number. I have to go now, perhaps you can tag others to continue. You're doing fine so far.
wait can I just tell you what I think the answer is
I am here now xD
yay thank you
if you look at the choices I dont think were doing this right -2y + 6 2y - 6 2y + 6 -2y - 6
Hmm well the question didn't ask to solve for a variable..
right
It says to isolate x in -x + 2y = -6
yeah so do I just subtract 2y from both sides
\(\color{blue}{\text{Originally Posted by}}\) @mathmate Given: -x + 2y = -6 3x + y = 8 From first equation: -x + 2y = -6 2y+6=x or \(\color{red}{x}=\color{red}{(2y+6)}\) Substitute into second equation: \(3(\color{red}{2y+6} )+ y = 8\) Distribute the multiplication by 3 and solve for y. \(\color{blue}{\text{End of Quote}}\) The answer is in red.. lol
But we have -x + 2y = -6
Oh I feel stupid thank you
We could just add x and add 6 on both sides.
so thats not the answer
-x + 2y = -6 +x +x ------------- 2y= -6 + x 2y = -6 + x +6 +6 ----------- 2y+6 = x
It is.
of thank you
oh*
np :)
can u help me with another one please
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