Name 2 complex fractions that equal to x-3/x+4
I hope you mean compound fraction because I know what that means here is a hint \[\frac{x-3}{x+4} =\frac{\frac{x-3}{1}}{\frac{x+4}{1}}\]
oh, I was thinking about multiplying by some complex number to get the same result
\[\frac{x-3}{x+4} =\frac{\frac{x-3}{a(x)}}{\frac{x+4}{a(x)}} \]
what about \[\frac{x}{x + 4} - \frac{3}{x + 4} \] perhaps its to simple.
can you explain the a(x) in your formula
It is a function of x
\[\frac{x-3}{x+4} =\frac{\frac{x-3}{1}}{\frac{x+4}{1}} \cdot \frac{\frac{1}{a(x)}}{\frac{1}{a(x)}} =\frac{\frac{x-3}{a(x)}}{\frac{x+4}{a(x)}}\]
im pretty sure a complex fraction has to consist of a fraction on top of a fraction
(x-3)/a is a fraction (x+4)/a is a fration
I've never heard of a camplex fraction so I think of imaginary numbers since they are called complx
Let me clear this up thanks to purplemath http://www.purplemath.com/modules/compfrac.htm
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