factor 12x^2 -48
@Nnesha @campbell_st @FibonacciChick666
divide by 12 leaving u with x^2-4 now factor like before
Since you have two value it either has to be a difference of squares or it has a common factor. This is not a difference of squares, so take out the common factor and leave the rest in parenthesis. Simplify from their if needed.
can you take anything out of both terms? do they have a common divisor?
(x-2)(x+2) correct?
no, almost
Yes, but you still have to have the greates common factor on the outside.
you cannot forget what you factor from the original
12?
so remember the xy 3xy problem?
yes
similar here only the 12 is your 3xy and whatever you factor the inside to is your xy. You should have 3 terms when you are done in this form (#)(___)(___)
lol lucky @Nnesha
Yes, 12 was the greatest common factor. You're (x+2)(x-2) is correct, but you still have to have the 12. Otherwise, when you solve the equation, you will not get the unfactored form as you will not have distributed the 12.
so where do i put the 12 at
The 12 would be on the outside of the parenthesis, which allows you to distribute it.
like this 12(x-2)(x+2) ?
yes good job
Yes! Also an easy way to check if your answer is right is to simplify your factored equation. If it simplifies to your original equation, you have the right answer!
thanks guys i really appreciate ur help :) @Nnesha @acxbox22 @Mantis_Shrimp @FibonacciChick666 hope i could medal all of u
;) no problem
np
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