PLEASE HELP!!!!! can someone please help me find the hole in the equation
(-2x^2+8)/(3x+6)

Question

PLEASE HELP!!!!! can someone please help me find the hole in the equation
(-2x^2+8)/(3x+6)

anonymous · Answer

guess

anonymous · Answer

yay you're back!

anonymous · Answer

hint
factor
cancel

anonymous · Answer

although this one takes more work to factor and cancel, but not much more

anonymous · Answer

alright...
-2(x^2+8)/3(x+2)

anonymous · Answer

shoot i really dont know how to factor that out

anonymous · Answer

you made a mistake in the numerator is why

anonymous · Answer

oh! i see it

anonymous · Answer

-2(x^2-8)/3(x+2)

anonymous · Answer

nope try again

anonymous · Answer

the 8 is wrong...

anonymous · Answer

OOOOO!

anonymous · Answer

-2(x^2-4)/3(x+2)

anonymous · Answer

whew now you can factor right?

anonymous · Answer

we cross out (x+2) and get
-2(x-2)/3

anonymous · Answer

got it

anonymous · Answer

so there is no vertical symptote

anonymous · Answer

nope

anonymous · Answer

cause there's no x in the denominator

anonymous · Answer

it is just a line

anonymous · Answer

shoot can you help me with that then

anonymous · Answer

make it look like a line?

anonymous · Answer

no, the vertical saymptote, who would i find it?

anonymous · Answer

i'm also a little confused with the hole. i know the x=-2 but how would i find the y value?

anonymous · Answer

plug it in to $\frac{-2(x-2)}{3}$

anonymous · Answer

i got 2.66666666..7 how would i plug that into a coordinate? use the fraction 8/3?

anonymous · Answer

so the hole would be (-2,(8/3))

anonymous · Answer

yes

anonymous · Answer

awsom

anonymous · Answer

so how would i find the vertical asymptote?

anonymous · Answer

you need an example with a denominator that does not cancel

anonymous · Answer

but this denominator did cancel right??/

anonymous · Answer

right 
that is why  there is NO  vertcal asymptote

anonymous · Answer

sorry, one more thing with this question i found the x intercept to be (2,0)

anonymous · Answer

and the y intercept to be (0, (8/3))

anonymous · Answer

yeah you do that on in your head since it is already nicely factored for you

anonymous · Answer

so both are correct?

anonymous · Answer

no i think if  $x=0$ then $y=\frac{4}{3}$

anonymous · Answer

oh cause i have to reduce?

anonymous · Answer

no because that is just what you get
there is no 8 in it

anonymous · Answer

yes i figured it out just a moment ago. THANK YOU you've been a great help @satellite73