Where am I going wrong? Please help 1. Research the highest interest rate (APY—annual percent yield) for 2-year and 5-year CDs. Document the company's name, interest rate, and minimum investment. The minimum investment must be less than or equal to $5,000.
This is what I have so far from my researched company. Discover Bank: 1.15%, $2,500 2-year CD Discover Bank: 2.10%, $2,500 5-year CD
To follow up, it says to create a function that represents this scenario for the 2-Year CD & 5-Year Cd and show how much you will be paid when the CD matures. This is my work thus far, but it seems fishy, it looks too good to be true? F(x) = 2500(1.15)^2 = 2500(1.32) = $3,300 F(x) = 2500(2.10)^5 = 2500(40.84) = $102,100
I wish I could help you out, but I don't know anything about economics type stuff. Good luck, hopefully someone shows up soon, if not maybe try checking back tomorrow and bumping it?
your equations are right use 5000 rather than 2500. https://prezi.com/xjfsynwyj39m/407-407-exploring-linear-and-exponential-growth/ exact same problem here expand the comments
What formula are you using, can you write it out without the values but with variables in their stead?
F(x) = a * (r) ^ x it could be that, if that makes more sense @Algorithmic
Does that work for annual percent yield? If I recall correctly: \[APY = (1 + \dfrac{r}{n})^n - 1\] Let \(r\) be rate. Let \(n\) be compound periods per year. So now plug it all in: \[APY = (1 + \dfrac{0.0115}{2})^2 - 1\] \[0.0115330625 = 1.1533062\%\] \($2,500 * 0.0115330625 = $28.83\) earning? That seems awfully small...
Exactly this is where I'm stuck, however that formula seems to make sense, It makes more sense then making over $100,000 from only 2,500 in 5 years however
That would mean that for the 5 Year CD it would be APY = (1 + 0.0210 / 5) ^ 5 - 1 correct?
Let me calculate for the second one, however I am still skeptical we are using the correct formula. \[APY = (1 + \dfrac{r}{n})^n - 1\] \[APY = (1 + \dfrac{0.021}{5})^5 - 1\] \[APY = 0.02117714243715491232\] \[0.02117714243715491232 = 2.11771424371549123\%\] \[2,500 * 0.02117714243715491232 = 52.9428560928872808~earning?\] Five years should yield one more money, I think I am calculating something wrong. Let me try Google for some help, LOL.
Honestly its such a mind freak, LOL.
Indeed. Do you know under what chapter you are learning this? Maybe that could hint us in what we need to do?
Its called 04.07 Exploring Linear and Exponential Growth in Algebra I
Hmm, so it defiantly will not need my original thought of a economics formula, rather something with exponential growth/decay.
Well the formula you gave me was mentioned in the lesson, However I'm not sure if it would. apply to this scenario. the $52 increase for 5 years may be correct because of this scenario as well, 3. An investor comes to your office. He says that if you give him the $5,000, he will add on an additional $50 each year to what he owes you. Create the function for this investor's plan. F(x) = 5000 + 50x
Working this out on paper, I work better that way. Just a second.
That is fine, I am very thankful for your help!
This seems more right, so I hope it is. Actual formula for exponential growth: \[y = a_i(1 + r)^n\] \(a_i = Initial~amount.\) \(r = Rate.\) \(n = Number~of~years~aka~time~of~growth.\) Let: \(a_i = 2,500\) \(r = 1.15\% \rightarrow 0.0115\) \(n = 2\) So: \[y = 2,500(1 + 0.0115)^2 = 2557.83\] I tried for the second equation, and it works too. Try it, and I will confirm on your answer.
Alright so, A= 2,500 R= 1.21% > 0.021 N = 5 y = 2500 (1 + 0.021) ^ 5 = $2773.7589 = $2774 ??
Close but: 1.21% = 0.0121.
Y = 2500 (1 + 0.0121) ^ 5 = 2654.9548 = $2655?
Correct! \[y = 2500(1 + 0.0121)^5\] \[y = 2500(1 + 0.0121)^5\] \[(1 + 0.0121)^5 = 1.06198192304881474601\] \[y = 2500 * 1.06198192304881474601\] \[y = 2654.954807622036865025\]
THANK YOU SO MUCH!!! That makes much more logical sense & I completely see where I went wrong & will forever learn from this mistake! @Algorithmic you are the best! Have i already awarded you your much earned medal?
No problem, just glad I was of help. It was a nice refresher on exponential growth and decay for me. :-) Peace.
Join our real-time social learning platform and learn together with your friends!