Determine which relation is a function. A. {(–4, 3), (–2, 3), (–1, 2), (2, 5), (3, 2)} B. {(–4, 1), (–2, 3), (–2, 1), (–1, 5), (3, 2)} C. {(–4, 1), (–2, 3), (–1, 2), (3, 5), (3, 2)} D. {(–4, 1), (–2, 3), (–1, 1), (–1, 5), (3, 2)}
I can help
First of all, you need to know what a function is.
Do you?
no not really
Ok. To make it quick I will tell you that all the first numbers listed can't repeat. To be a function they all have to be different
You will have to find it yourself. Just check to see if any of the numbers listed first repeat.
it would be c
What's really funny is that I just did this in school within the last few days. where do you go? I go to LSS(Laurel Springs online School)
OVCA(Oklahoma Virtural Charter Academy)
Oh. So both online school. Cool
Now, which one did you find was a function based off of my brief explanation?
C?
The first numbers are your input, the others your output. Think of a function like a vending machine. For each input, there is an output. 3 would give you chips, 2 would give cookies, 4 would give a soda.... Each input value has to have it's own output value. If you have more than 2 of the same inputs, then you would get seperate things. So if you selected for example 5, on a vending machine you could get crackers or something else. Think of a function that way.
Not C, there are 2 threes
Try again. Just focus on the input values
D?
And in a relation, you list the inputs least to greatest. And if a number repeats you write it once. For example if my input values are 3,3, 6,-1, and 0 I would write them as -1,0,3,6. Ok?
No look one more time
b
It listed -1 twicce
*twice
No, A. Your input values in A were 14, -2, -1, 2, 3. None repeated. You want to write them out to check so you can see if any repeat
*-4 not 14
but B could be the only one because youou said earlier the a was not going to be it
no
When?
Because A is defiantly the answer. I knew that the whole time so I wouldn't have said it isn't
Ok. To make it quick I will tell you that all the first numbers listed can't repeat. To be a function they all have to be different
But in A they all are different and I never said in that post that A wasn't
Oh you might have been looking at the output values in the others...
Only the input values, the numbers written before the comma, matter when seeing if a relation is a function
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