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Let f(x) = 2x + 2. Solve f-1(x) when x = 4.
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that means solve \[2x+2=4\] should easy enough right?
but inverted...
f^-1(x)
yeah i know
you are not plugging in 4, you are solving for x if \[2x+2=4\]
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takes two steps, subtract 2, divide by 2
no, when it says to solve for x=2 you insert 2 for x: f(4)=2(4)+2
x = 1 ?
trust me on this let me know what you get then i will show you why that answer is right
er x =4
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i got x = 1 @satellite73
?
yes \(x=1\)
that means that \[f^{-1}(4)=1\]in other words if \(f(x)=2x+2\) then \(f(1)=4\) which is true
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