A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm^3 and the temperature of the gas increases to 308 K?
a. 0.86 atm
b. 0.95 atm
c. 1.0 atm
d. 1.1 atm

Question

A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm^3 and the temperature of the gas increases to 308 K? 
a. 0.86 atm 
b. 0.95 atm 
c. 1.0 atm 
d. 1.1 atm

anonymous · Answer

I need help ASAP plz! :(

mrnood · Answer

The general equation for gas state is

PV/T is constant

SO 

$$\frac{ P _{1}V _{1} }{ T _{1} }=\frac{ P _{2}V _{2} }{ T _{2} }$$

In oyur case 
P1=.98atm
V1= 212cm^3
T1 = 293K

P2= unknown
V2 = 196cm^3
T2= 308K

SO there is only one unknown in my equation above : OS solve for P2

mrnood · Answer

correction to above:
SO there is only one unknown in my equation above :  solve for P2

anonymous · Answer

thnx :)