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Chemistry 18 Online
OpenStudy (anonymous):

HELP PLEASE GET MEDALS AND I'LL FAN YOU A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral fragment?

OpenStudy (anonymous):

1. 0.20 g/cm^3 2. 5.74 g/cm^3 3. 5.00 g/cm^3 4. 164g/cm^3

OpenStudy (anonymous):

@FluffyPancakeTerd

OpenStudy (anonymous):

Please help hurry, if you can.

OpenStudy (anonymous):

Use the Density formula D= m/v

OpenStudy (anonymous):

D = mass/volume your mass is 14.4gvright and your volume is 5.74cm3 so then you do this 14.4/5.74 = D and you get this 2.51 g/cm3

OpenStudy (anonymous):

Does this help?

OpenStudy (anonymous):

I messed up thats not an answer

OpenStudy (anonymous):

let me look again.

OpenStudy (anonymous):

wait no im good.

OpenStudy (anonymous):

Did you get it

OpenStudy (anonymous):

Yes, the answer six was right thank you!

OpenStudy (anonymous):

np

OpenStudy (anonymous):

Did you get the answer for this one.

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