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OpenStudy (anonymous):
How many grams are in 8.91*10^24 atoms of Xe
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OpenStudy (anonymous):
You have to use avogadro's numbers 6.022x10^23 to get to moles 8.91*0&24 atom Xe | 1mol | 6.022 *10^23 = 14.795 mols
OpenStudy (anonymous):
Then get moles to grams 14.795 mol Xe | 131.29 g Xe | 1 mol Xe = 1942 g Xe I think this is correct
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