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Mathematics 8 Online
OpenStudy (haleyelizabeth2017):

Simplify the expression. It is using imaginary numbers.

OpenStudy (haleyelizabeth2017):

\[\frac{ 3+4i }{ 2+4i }\]

OpenStudy (anonymous):

still need help?

OpenStudy (haleyelizabeth2017):

Yep :)

OpenStudy (anonymous):

multiply numerator and denominator by conjugate of denominator. so bascially just do \[\frac{ 3+4i }{ 2+4i }\cdot\dfrac{2-4i}{2-4i}\] and simplify from there

OpenStudy (haleyelizabeth2017):

Okay....give me a second :)

OpenStudy (haleyelizabeth2017):

for the numerator, would it be \(+~or~-~4i^2?\)

OpenStudy (haleyelizabeth2017):

I think -.....

OpenStudy (anonymous):

-, yes, but actually \(-16i^2\)

OpenStudy (haleyelizabeth2017):

whoops lol I forgot to multiply the coefficients lol

OpenStudy (anonymous):

for numerator, you should got \(6+8i-12i-16i^2\)

OpenStudy (anonymous):

then simplify, you get it

OpenStudy (haleyelizabeth2017):

yep so when you combine like terms and simplify, you get 22-4i

OpenStudy (anonymous):

correct

OpenStudy (haleyelizabeth2017):

and then the denominator simplifies to 22, correct?

OpenStudy (haleyelizabeth2017):

I mean 20 lol

OpenStudy (anonymous):

\((2+4i)(2-4i) = 4-16i^2 = 20\)

OpenStudy (anonymous):

yeah

OpenStudy (haleyelizabeth2017):

haha okay. Thank you! :)

OpenStudy (anonymous):

no problem

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