What is the 15th term in the sequence? 3, 12, 48, 192, 768, . . .
iknow the answer i just need to know if its right
i know the ratio to 3 and 12 is 9 but now i see theirs 48 and 192 so i dont understand it now
Two types of sequences are arithmetic and geometric. In an arithmetic sequence, the same number is added to each term to get the following term. In a geometric sequence, the same number is multiplied by each term to get the following term.
oooh so 9 is being multiplied
First, we need to find out if this is an arithmetic sequence or a geometric sequence. If this is an arithmetic sequence, then you are ***adding*** the same number to each term to get the next term. What do you add to 3 to get 12? What do you add to 12 to get 48? Are they the same number in each case?
no
9 is not being multiplied. 9 * 3 is not equal to 12
this is a geometric progression to get from one number to the next in the sequence you multiply by the same factor this factor is called the common ratio
Correct. 3 + 9 = 12 12 + 36 = 48 Since 9 and 36 are definitely not the same number, this is not an arithmetic sequence.
Now let's determine if this is a geometric sequence. In a geometric sequence, we multiply each term by the same number to get the next term. What do you multiply 3 by to get 12?
4
Great. What do you multiply 12 by to get 48?
just like the other problem when you divide you will find r the first term is a is given =3
4
Great. If you continue to multiply by 4, you will get 192, 768, 3072, etc.
what would i be dividing @triciaal
Now we know this is a geometric sequence. One way of finding the 15th term is to just keep multiplying each term you get by 4 and counting the terms until you get to the 15th term.
thank you im writing this stuff down so give me one second
Another way of doing it is to use a formula. Here is the formula to find the nth term: \(a_n = a_0r^{n - 1}\) where \(a_0\) is the first term; \(r\) is the common ratio; \(a_n\) is the desired \(n^{th} \) term.
and what is the common ration in this case?
4
@mathstudent55 i solved the equation and i got 201326592 is this correct?
@Nnesha
I get 805,306,368 I multiplied by 4 one more time than you did.
@MiggityMiggityMac yes^^^^that's what i'm telling u
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