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Mathematics 20 Online
OpenStudy (idku):

What are the guidelines on integration by parts?

OpenStudy (idku):

I know that: when you have (for example) : \[\int\limits_{ }^{ }\ln(x)~dx\] then your another function for by parts, is (will give it a notation,) g(x)=1. And you can not choose to differentiate g(x).

OpenStudy (idku):

I am asking, would I be allowed to? \[\int\limits_{ }^{ }x~dx=x^2-\int\limits_{ }^{ }x~dx\]\[\int\limits_{ }^{ }x~dx=x^2-x^2+\int\limits_{ }^{ }x~dx\]\[\int\limits_{ }^{ }x~dx=x^2-x^2+x^2-\int\limits_{ }^{ }x~dx\](if I am doing that correctly)

myininaya (myininaya):

\[\int\limits_{}^{}x dx=\int\limits_{}^{}1 x dx=x(x)-\int\limits_{}^{}x(1) dx \\ \text{ add on both sides the } \int\limits_{}^{}x dx \\ 2 \int\limits_{}^{}x dx=x(x) \\ \int\limits_{}^{}x dx=\frac{1}{2}x(x) \\ \int\limits_{}^{}x dx=\frac{1}{2}x(x)+C\]

myininaya (myininaya):

That could work for integrate x w.r.t x by integration by parts

myininaya (myininaya):

yours seems to be going in a circle

myininaya (myininaya):

\[n \neq -1 \\ \int\limits_{}^{}x^n dx=\int\limits_{}^{}1 x^{n} dx=x(x^n)-\int\limits_{}^{}x(n x^{n-1}) dx \\ \int\limits_{}^{}x^n dx=x(x^n)-n \int\limits_{}^{}x^{n} dx \\ \text{ add on both sides the } n \int\limits_{}^{}x^n dx \\ (n+1)\int\limits_{}^{}x^n dx=x(x^n) \\ \int\limits_{}^{}x^n dx=\frac{x(x^n)}{n+1}+C\]

myininaya (myininaya):

like you had it you just needed to add the integral thing on both sides in your first step

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