Question

Radical Multiplication Problem Help!
Medal to best answer.




Problem will be posted below.

Answer 1

\[2+\sqrt{6}\]
OVER
\[2-\sqrt{6}\]

Answer 2

hi

Answer 3

\[\frac{ 2 + \sqrt{6} }{ 2 - \sqrt{6} }\]

Answer 4

For these, you want to clear a radical from the denominator for a formal answer...

Do that by multiplying both the top and bottom by 2 + root(6) like this...

Answer 5

HI!! Exactly. I just didn't know hot to make that line.

Answer 6

\[\frac{ 2+\sqrt{6} }{ 2-\sqrt{6} }*\frac{2+\sqrt{6} }{ 2+\sqrt{6} } = \]

Answer 7

notice you are not changing the original fraction, you are multiplying it by 1,

Answer 8

2 plus root 6 over 2 plus root 6 is the same as 1

Answer 9

Do you always use the numerator?

Answer 10

you use the opposite sign in the denominator. there is a -, use a plus for this one.. watch what happens to the denominator when you distribute them together.. foil

Answer 11

\[\frac{ 2+\sqrt{6} }{ 2-\sqrt{6} }*\frac{2+\sqrt{6} }{ 2+\sqrt{6} } = \frac{ 4 + 2\sqrt{6}+2\sqrt{6}+\sqrt{6}\sqrt{6} }{ 4 +2\sqrt{6}-2\sqrt{6} -\sqrt{6}\sqrt{6} }\]

Answer 12

so I do foil like this:
\[(2+\sqrt{6})(2-\sqrt{6}\]

Answer 13

yeah, notice the denominator now has +2root6 - 2 root 6,, the root dissapears

Answer 14

the general trick is , if you have
\[a - \sqrt{b}\]
in the denominator, multiply the top and bottom by the opposite sign
a + root(b)

Answer 15

okay. so doing foil....
\[4-\sqrt{36}\]

Answer 16

yep, but notice the root simplifies,
\[\sqrt{n}\sqrt{n} = n\]

Answer 17

So...how does it look different?

Answer 18

\[\frac{ 2+\sqrt{6} }{ 2-\sqrt{6} }*\frac{2+\sqrt{6} }{ 2+\sqrt{6} } = \frac{ 4 + 2\sqrt{6}+2\sqrt{6}+\sqrt{6}\sqrt{6} }{ 4 +2\sqrt{6}-2\sqrt{6} -\sqrt{6}\sqrt{6} } = \frac{ 4 + 4\sqrt{6}+6 }{ 4 - 6 }\]

Answer 19

\[\frac{ 10 + 4\sqrt{6} }{ -2 }\]

Answer 20

now factor a -2 from the top

Answer 21

I don't really understand what the problem is doing from your third up message.

Answer 22

\[\frac{ 2(5+2\sqrt{6}) }{ -2 } = \frac{ -5 - 2\sqrt{6} }{ 1 }\]

Answer 23

k, ill go back

Answer 24

\[\frac{ 2+\sqrt{6} }{ 2-\sqrt{6} }*\frac{2+\sqrt{6} }{ 2+\sqrt{6} } = \]

Answer 25

I just don't really understand what happens form using foil to the fraction stuff. I get the first part you sent.

Answer 26

*from

Answer 27

when you foil distribute the top you get
\[4 + 2\sqrt{6 }+ 2\sqrt{6 } + \sqrt{6}\sqrt{6}\]

you see that part?