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Mathematics 20 Online
OpenStudy (beccab003):

Radical question.

OpenStudy (beccab003):

@DanJS

OpenStudy (danjs):

k

OpenStudy (beccab003):

\[\frac{ 60\sqrt{8} }{ \sqrt{2} }\]

OpenStudy (danjs):

Anytime you have a root by itself in the denominator, multiply the fraction by that root over itself.. like \[\frac{ a }{ \sqrt{b} } = \frac{ a \sqrt{b} }{ \sqrt{b}\sqrt{b} } = \frac{ a \sqrt{b} }{ b }\]

OpenStudy (danjs):

\[\frac{ 60\sqrt{8} }{ \sqrt{2} } * \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{ 60\sqrt{8}\sqrt{2} }{ 2 }\]

OpenStudy (danjs):

\[\frac{ 60\sqrt{8 * 2} }{ 2 } = \frac{ 60\sqrt{16} }{ 2 } = \frac{ 60 * 4 }{ 2 }\]

OpenStudy (beccab003):

Okay! That was easy! I understand everything except for why \[\sqrt{2}*\sqrt{2}\] equals 2?

OpenStudy (beccab003):

so the final answer is 120?

OpenStudy (danjs):

yeah remember this :

OpenStudy (danjs):

\[\sqrt{x}\sqrt{x} = x ^{1/2}*x ^{1/2} = x ^{\frac{ 1 }{ 2 }+\frac{ 1 }{ 2 }} = x^1 = x\] so \[\sqrt{x}\sqrt{x} = x\]

OpenStudy (beccab003):

oh yeah! I forgot!

OpenStudy (beccab003):

Can you do one or two more problems on a new thread? Only if it's okay with you.

OpenStudy (danjs):

sure, i think you are getting it

OpenStudy (danjs):

put up the one that looks the hardest

OpenStudy (beccab003):

this time I'll walk through it and tell me if a make a mistake.

OpenStudy (beccab003):

okay

OpenStudy (danjs):

k

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