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Mathematics
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OpenStudy (beccab003):
Radical question.
11 years ago
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OpenStudy (beccab003):
@DanJS
11 years ago
OpenStudy (danjs):
k
11 years ago
OpenStudy (beccab003):
\[\frac{ 60\sqrt{8} }{ \sqrt{2} }\]
11 years ago
OpenStudy (danjs):
Anytime you have a root by itself in the denominator, multiply the fraction by that root over itself.. like
\[\frac{ a }{ \sqrt{b} } = \frac{ a \sqrt{b} }{ \sqrt{b}\sqrt{b} } = \frac{ a \sqrt{b} }{ b }\]
11 years ago
OpenStudy (danjs):
\[\frac{ 60\sqrt{8} }{ \sqrt{2} } * \frac{ \sqrt{2} }{ \sqrt{2} } = \frac{ 60\sqrt{8}\sqrt{2} }{ 2 }\]
11 years ago
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OpenStudy (danjs):
\[\frac{ 60\sqrt{8 * 2} }{ 2 } = \frac{ 60\sqrt{16} }{ 2 } = \frac{ 60 * 4 }{ 2 }\]
11 years ago
OpenStudy (beccab003):
Okay! That was easy! I understand everything except for why
\[\sqrt{2}*\sqrt{2}\]
equals 2?
11 years ago
OpenStudy (beccab003):
so the final answer is 120?
11 years ago
OpenStudy (danjs):
yeah
remember this :
11 years ago
OpenStudy (danjs):
\[\sqrt{x}\sqrt{x} = x ^{1/2}*x ^{1/2} = x ^{\frac{ 1 }{ 2 }+\frac{ 1 }{ 2 }} = x^1 = x\]
so
\[\sqrt{x}\sqrt{x} = x\]
11 years ago
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OpenStudy (beccab003):
oh yeah! I forgot!
11 years ago
OpenStudy (beccab003):
Can you do one or two more problems on a new thread? Only if it's okay with you.
11 years ago
OpenStudy (danjs):
sure, i think you are getting it
11 years ago
OpenStudy (danjs):
put up the one that looks the hardest
11 years ago
OpenStudy (beccab003):
this time I'll walk through it and tell me if a make a mistake.
11 years ago
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OpenStudy (beccab003):
okay
11 years ago
OpenStudy (danjs):
k
11 years ago
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