someone plz help me with dividing this radical expression!

Question

anonymous · Answer

$$\sqrt[3]{\frac{ x^2 }{ 3y }}$$

ajspeller · Answer

You cannot simplify this anymore than it already is

anonymous · Answer

@ajspeller actually you can

ajspeller · Answer

Nothing breaks down.  You can rationalize for a different form but thats about it.

anonymous · Answer

@DanJS Can you plz help me?

anonymous · Answer

@poopsiedoodle @iPwnBunnies @pooja195 I REALLY NEED HELP!!

ipwnbunnies · Answer

Yeah, I don't see how you can simplify this anymore. There are 2 different variables in this expression, can't really do anything.

ipwnbunnies · Answer

It says I'm not allowed to access the page, or something.
It just looks like they added variables, they didn't find a solution of anything.
Maybe I'm not understanding the problem.

anonymous · Answer

@iPwnBunnies okay this is what this website, http://rohls.weebly.com/uploads/2/8/2/1/2821453/6-2formgkey.pdf , gave as the answer for this question: $$\frac{ \sqrt[3]{9x^2y^2} }{ 3y }$$ But how did they get this answer? I want to know the steps.

anonymous · Answer

$$\sqrt[3]{\frac{ x^2 }{ 3y }}
=\sqrt[3]{\frac{ x^2 }{ 3y } \cdot\frac{(3y)^2}{(3y)^2}} = \sqrt[3]{\frac{ 9x^2y^2 }{ (3y)^3 }} = \frac{\sqrt[3]{9x^2y^2}}{3y}
$$

anonymous · Answer

The previous question has to be simplified because you can't have the square root, cubed root, etc. .. of any number as the denominator.

anonymous · Answer

Rationalize the denominator.

ipwnbunnies · Answer

^^^
I guess I didn't understand the problem lol.

anonymous · Answer

@wio now I understand. Thank you so much!